3x^3/5=48x^-1/5

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Solution for 3x^3/5=48x^-1/5 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x^3)/5 = (48*x^-1)/5 // - (48*x^-1)/5

(3*x^3)/5-((48*x^-1)/5) = 0

(3*x^3)/5+(-48/5)*x^-1 = 0

3/5*x^3-48/5*x^-1 = 0

(3/5*x^4-48/5*x^0)/(x^1) = 0 // * x^2

x^1*(3/5*x^4-48/5*x^0) = 0

x^1

(3/5)*x^4-48/5 = 0

(3/5)*x^4-48/5 = 0 // * 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 16, -16, 24, -24, 48, -48 }

1

x = 1

3*x^4-48 = -45

1

-1

x = -1

3*x^4-48 = -45

-1

2

x = 2

3*x^4-48 = 0

2

x-2

3*x^3+6*x^2+12*x+24

3*x^4-48

x-2

6*x^3-3*x^4

6*x^3-48

12*x^2-6*x^3

12*x^2-48

24*x-12*x^2

24*x-48

48-24*x

0

3*x^3+6*x^2+12*x+24 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 24, -24 }

1

x = 1

3*x^3+6*x^2+12*x+24 = 45

1

-1

x = -1

3*x^3+6*x^2+12*x+24 = 15

-1

2

x = 2

3*x^3+6*x^2+12*x+24 = 96

2

-2

x = -2

3*x^3+6*x^2+12*x+24 = 0

-2

x+2

3*x^2+12

3*x^3+6*x^2+12*x+24

x+2

-3*x^3-6*x^2

12*x+24

-12*x-24

0

3*x^2+12 = 0

DELTA = 0^2-(3*4*12)

DELTA = -144

DELTA < 0

x in { 2, -2}

x in { 2, -2 }

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